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Comparison of radiographic and computed tomographic measurement of pedicle and vertebral body dimensions in Koreans: the ratio of pedicle transverse diameter to vertebral body transverse diameter

机译:朝鲜人椎弓根和椎体尺寸的射线照相和计算机断层扫描比较:椎弓根横向直径与椎体横向直径之比

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摘要

This study was designed to investigate the characteristics of pedicle transverse diameters (PD), vertebral body transverse diameters (VBD), especially the ratios of PD/VBD (CT ratio), which has never been discussed, in Koreans using computed tomography (CT) scans and to evaluate the possibility of obtaining more accurate estimations of PD from plain radiographs using the CT ratios in each spine level. The T1–L5 vertebrae of 50 participants were analyzed prospectively with CT scans (CT-VBD and CT-PD), and the T9–L5 vertebrae of the same participants were investigated with plain radiographs (X-VBD and X-PD). The CT ratio had a higher correlation with the CT-PD (r2 = 0.630) from T1 to L5, especially in the lower thoracic and lumbar spine (T9–L5, r2 = 0.737). The correlation of VBDs between the two radiologic tools (r2 = 0.896) was higher than that of the PDs (r2 = 0.665). Based on the data, equations for the estimation of a more accurate PD from plain radiographs were developed as follows: estimated PD = estimated VBD × [1.014 × (X-VBD) + 0.152] × the mean CT ratio at each spinal level. The correlation between the estimated PD and the CT-PD (r2 = 0.852) was improved compared with that (r2 = 0.665) between the X-PD and the CT-PD. In conclusion, the CT ratio showed a very similar changing trends to CT-PD from T1 to L5 regardless of sex and body mass, and the measurement error of PD from only plain radiographs could be minimized using estimated VBD and the mean CT ratio at each spinal level.
机译:这项研究旨在调查韩国人使用计算机断层扫描(CT)的椎弓根横向直径(PD),椎体横向直径(VBD)的特征,尤其是PD / VBD的比率(CT比率),这从未有过讨论。扫描并评估使用每个脊柱水平的CT比从平片上获得更准确的PD评估的可能性。通过CT扫描(CT-VBD和CT-PD)前瞻性分析了50名参与者的T1-L5椎骨,并用平片(X-VBD和X-PD)研究了同一参与者的T9-L5椎骨。从T1到L5,CT比与CT-PD(r2 = 0.630)有更高的相关性,特别是在下胸部和腰椎(T9–L5,r2 = 0.737)。两种放射学工具之间VBD的相关性(r2 = 0.896)高于PD的相关性(r2 = 0.665)。根据这些数据,可以开发出如下的公式来从平片上估算出更精确的PD:估算的PD =估算的VBD×[1.014×(X-VBD)+ 0.152]×每个脊柱水平的平均CT比。与X-PD和CT-PD之间的相关性(r2 = 0.665)相比,估算的PD和CT-PD之间的相关性(r2 = 0.852)得到了改善。总之,无论性别和体重,CT比率从T1到L5的变化趋势都与CT-PD非常相似,并且使用估计的VBD和每个位置的平均CT比率可以将仅来自平片的PD的测量误差最小化。脊柱水平。

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